k(k^2-9)-2(2k-9)+2(6-3k)=0

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Solution for k(k^2-9)-2(2k-9)+2(6-3k)=0 equation: 



k(k^2-9)-2(2k-9)+2(6-3k)=0

We add all the numbers together, and all the variables

k(k^2-9)-2(2k-9)+2(-3k+6)=0

We multiply parentheses

k^3-9k-4k-6k+18+12=0

We do not support ekpression: k^3

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